In a water-cooled condenser scenario, 10 lbs of refrigerant loses 20 BTU per lb, and 10 lbs of water passes through with the entering water at 80°F. What is the water leaving temperature?

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Multiple Choice

In a water-cooled condenser scenario, 10 lbs of refrigerant loses 20 BTU per lb, and 10 lbs of water passes through with the entering water at 80°F. What is the water leaving temperature?

Explanation:
In a water-cooled condenser, the refrigerant gives up heat to the water, so you compare the heat lost by the refrigerant to the heat gained by the water. The refrigerant loses 10 lb × 20 BTU/lb = 200 BTU. This energy goes into heating 10 lb of water. Water has a specific heat of about 1 BTU/(lb·°F), so the temperature rise of the water is ΔT = Q / (m·Cp) = 200 / (10 × 1) = 20°F. With entering water at 80°F, the leaving water temperature is 80°F + 20°F = 100°F.

In a water-cooled condenser, the refrigerant gives up heat to the water, so you compare the heat lost by the refrigerant to the heat gained by the water. The refrigerant loses 10 lb × 20 BTU/lb = 200 BTU. This energy goes into heating 10 lb of water. Water has a specific heat of about 1 BTU/(lb·°F), so the temperature rise of the water is ΔT = Q / (m·Cp) = 200 / (10 × 1) = 20°F. With entering water at 80°F, the leaving water temperature is 80°F + 20°F = 100°F.

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